Shawn Zhong

Shawn Zhong

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Shawn Zhong

钟万祥
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Mathematics

Home / Notes / Mathematics / Page 17

Math 521 – 4/11

  • Apr 20, 2018
  • Shawn
  • Math 521
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Theorem 3.55 • Statement ○ If Σa_n is a series of complex numbers which converges absolutely ○ Then every rearrangement of Σa_n converges to the same sum • Proof ○ Let Σa_n^′ be a rearrangement of Σa_n with partial sum s_n^′ ○ By the Cauchy Criterion, given ε0, ∃N∈N s.t. § ∑_(i=n)^m▒|a_i | ε,∀m,n≥N ○ Choose p s.t. 1,2,…,N are all contained in the set {k_1,k_2,…,k_p } ○ Where k_1,…,k_p are the indices of the rearranged series ○ Then if np, a_1,…,a_N will be cancelled in the difference s_n−s_n^′ ○ So, |s_n−s_n^′ |≤ε⇒{s_n^′ } converges to the same value as {s_n } Limit of Functions • Definition ○ Let X,Y be metric spaces, and E⊂X ○ Suppose f:E→Y and p is a limit point of E ○ We write § f(x)→q as x→p, or § (lim)_(x→p)⁡f(x)=q ○ If ∃q∈Y s.t. § Given ε0, there exists δ0 s.t. § If 0d_X (x,p)δ, then d_Y (f(x),q)ε • Note ○ 0d_X (x,p)δ is the deleted neighborhood about p of radius δ ○ d_X and d_Y refer to the distances in X and Y, respectively • Relationship with sequence ○ Theorem 4.2 relates this type of limit to the limit of a sequence ○ Consequently, if f has a limit at p, then its limit is unique Theorem 4.3 • If f,g are complex function on E, we have • (f+g)(x)=f(x)+g(x) • (f−g)(x)=f(x)−g(x) • (fg)(x)=f(x)g(x) • (f/g)(x)=f(x)/g(x) where g(x)≠0 on E Theorem 4.4 (Algebraic Limit Theorem) • Let X be a metric space, E⊂X • Suppose p be a limit point of E • Let f,g be complex functions on E where ○ lim_(x→p)⁡f(x)=A ○ lim_(x→p)⁡g(x)=B • Then ○ lim_(x→p)⁡(f(x)+g(x))=A+B ○ lim_(x→p)⁡(f(x)g(x))=AB ○ lim_(x→p)⁡(f(x)/g(x) )=A/B where B≠0
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Math 541 – 4/18

  • Apr 20, 2018
  • Shawn
  • Math 541
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Proposition 64 • Statement ○ Let n 0 ○ Every nonzero element in Z\/nZ is either a unit or a zero-divisor • Note ○ We don’t have this property in Z ○ In Z, the units are ±1, there are no zero-divisor ○ 2∈Z is not 0 or unit or zero-divisor • Proof ○ Suppose a ̅∈Z\/nZ is nonzero and not a unit ○ Then d≔(a,n) 1 ○ Write cd=a,md=n ○ Then a ̅m ̅=c ̅d ̅m ̅=c ̅n ̅=0 ̅ ○ Moreover, m ̅≠0 ̅ § Since md=n,1≤m≤n, and d 1 § m cannot be a multiple of n Field • Definition ○ Communitive ring R is called a field if ○ Every nonzero element of R is a unit ○ i.e. Every nonzero element of R have a multiplicative inverse • Examples ○ Q,R ○ ℂ § But not true for R2 with (r_1,r_2 )(r_1^′,r_2^′ )=(r_1 r_1^′,r_2 r_2^′ ) ○ Z\/pZ (p prime) § 1≤a≤p−1,(a,p)=1⇒a ̅∈Z\/pZ § Note: Z\/nZ is a field ⟺ n is prime Product Ring • If R_1,R_2 are rings, R_1×R_2 has the following ring structure • For addition, it s just the product as groups • For multiplication, (r_1,r_2 )(r_1^′,r_2^′ )=(r_1 r_1^′,r_2 r_2^′ ) with identity (1_(R_1 ),1_(R_2 ) ) Integral Domain • Definition ○ A communicative ring R is an integral domain (or just domain) if ○ R contains no zero-divisors • Example ○ Unites are not zero-divisors, so fields are domains ○ Z is a domain ○ Z\/nZ is a domain ⟺ it is a field ○ R_1×R_2 is a domain ⟺ one of them is trivial, and the other is a domain
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Math 541 – 4/16

  • Apr 18, 2018
  • Shawn
  • Math 541
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Ring • Example 1 ○ The trivial group, equipped with the trivial multiplication, is a ring ○ It
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Math 541 – 4/11

  • Apr 18, 2018
  • Shawn
  • Math 541
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Ring • Definition ○ A ring is a set R equipped with two operations § +:R×R→R § ⋅:R×R→R ○ such that § (R,+) is an abelian group § ⋅ is associative § ∃1∈R s.t. 1⋅r=r=r⋅1 § Distributive property: □ ∀a,b,c∈R □ a⋅(b+c)=a⋅b+a⋅c □ (a+b)⋅c=a⋅c+b⋅c • Notes ○ 1 is called the multiplicative identity ○ Dummit-Foote don t require the multiplicative identity ○ ⋅ is not necessarily commutative ○ R is not a group under ⋅, because inverses may not exist ○ We will typically denote multiplication of r,s∈R by rs ○ Typically 1 will denote the multiplicative identity ○ And 0 will denote the identity of (R,+)
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9.1 Relations and Their Properties

  • Apr 18, 2018
  • Shawn
  • Math 240
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Binary Relations • Definition ○ A binary relation R from a set A to a set B is a subset R⊆A×B. • Example ○ Let A={0,1,2} and B={a,b} ○ {(0, a), (0, b), (1, a), (2, b)} is a relation from A to B. ○ We can represent this relation graphically or using a table: • Note ○ Relations are more general than functions ○ A function is a relation where exactly one element of B is related to each element of A Binary Relation on a Set • Definition ○ A binary relation R on a set A is a subset of A×A or a relation from A to A. • Example 1 ○ Suppose that A={a,b,c} ○ Then R={(a,a),(a,b), (a,c)} is a relation on A • Example 2 ○ Let A={1, 2, 3, 4} ○ The ordered pairs in the relation R={(a,b)│a divides b} are ○ {(1,1), (1, 2), (1,3), (1, 4), (2, 2), (2, 4), (3, 3),(4,4)} • Question: How many relations are there on a set A? ○ Because a relation on A is the same thing as a subset of A×A ○ We count the subsets of A×A. ○ Since A×A has n^2 elements when A has n elements ○ And a set with m elements has 2^m subsets ○ There are 2^(|A|^2 ) subsets of A×A. ○ Therefore, there are 2^(|A|^2 ) relations on a set A. • Example 3 ○ Consider these relations on the set of integers: § R_1={(a,b)│a≤b} § R_2={(a,b)│a b} § R_3={(a,b)│a=b or a=−b} § R_4={(a,b)│a=b} § R_5={(a,b)│a=b+1} § R_6={(a,b)│a+b≤3} ○ Note § These relations are on an infinite set and each of these relations is an infinite set § R_5 can be viewed as a function § Our definition of a function f:A→B is a subset of A×B § Therefore every function is a relation ○ Which of these relations contain each of the pairs § (1,1), (1, 2), (2, 1), (1, −1), and (2, 2)? ○ Solution § (1,1) is in R_1, R_3, R_4, and R_6 § (1,2) is in R_1 and R_6 § (2,1) is in R_2, R_5, and R_6 § (1, −1) is in R_2, R_3, and R_6 § (2,2) is in R_1, R_3, and R_4 Reflexive Relations • Definition ○ R is reflexive if and only if (a,a)∈R for every element a∈A ○ Written symbolically, R is reflexive if and only if ○ ∀x[x∈U→(x,x)∈R] • Note ○ If A = ∅ then the empty relation is reflexive vacuously. ○ That is the empty relation on an empty set is reflexive! • Example ○ The following relations on the integers are reflexive: § R_1={(a,b)│a≤b} § R_3={(a,b)│a=b or a=−b} § R_4={(a,b)│a=b} ○ The following relations are not reflexive: § R_2={(a,b)│a b} (note that 3 ≯ 3) § R_5={(a,b)│a=b+1} (note that 3 ≠ 3 + 1) § R_6={(a,b)│a+b≤3} (note that 4+4≰3) Antireflexive Relations • Definition ○ R is antireflexive if and only if (a,a)∉R for every element a∈A ○ Written symbolically, R is antireflexive if and only if ○ ∀x[x∈U→(x,x)∉R] • Note ○ Antireflexive is different from not reflexive • Example ○ The following relations on the integers are antireflexive § R_2={(a,b)│a b} § R_5={(a,b)│a=b+1} ○ R_6={(a,b)│a+b≤3} is neither reflexive nor antireflexive Symmetric Relations • Definition ○ R is symmetric if and only if (b,a)∈R whenever (a,b)∈R,∀a,b∈A ○ Written symbolically, R is symmetric if and only if ○ ∀x∀y[(x,y)∈R→(y,x)∈R] • Example ○ The following relations on the integers are symmetric: § R_3={(a,b)│a=b or a=−b} § R_4={(a,b)│a=b} § R_6={(a,b)│a+b≤3} ○ The following are not symmetric: § R_1={(a,b)│a≤b} (note that 3 ≤ 4, but 4 ≰ 3) § R_2={(a,b)│a b} (note that 4 3, but 3 ≯ 4) § R_5={(a,b)│a=b+1} (note that 4 = 3 + 1, but 3 ≠ 4 + 1) Antisymmetric Relations • Definition ○ R is antisymmetric if and only if a=b whenever (a,b),(b,a)∈R,∀a,b∈A ○ Written symbolically, R is antisymmetric if and only if ○ ∀x∀y[(x,y)∈R∧(y,x)∈R→x=y] • Note ○ For any integer, if a≥b and a≤b, then a=b • Example ○ The following relations on the integers are antisymmetric: § R_1={(a,b)│a≤b} § R_2={(a,b)│a b} § R_4={(a,b)│a=b} § R_5={(a,b)│a=b+1} ○ The following relations are not antisymmetric: § R_3={(a,b)│a=b or a=−b} (note that (1,−1),(−1,1)∈R_3) § R_6={(a,b)│a+b≤3} (note that (1,2),(2,1)∈R_6) Transitive Relations • Definition ○ R is transitive if and only if (a,c)∈R whenever (a,b),(b,c)∈R, ∀a,b,c∈A ○ Written symbolically, R is transitive if and only if ○ ∀x∀y∀z[(x,y)∈R∧(y,z)∈R→(x,z)∈R] • Note ○ For every integer, a≤b and b≤c, then b≤c • Example ○ The following relations on the integers are transitive: § R_1={(a,b)│a≤b} § R_2={(a,b)│a b} § R_3={(a,b)│a=b or a=−b} § R_4={(a,b)│a=b} ○ The following are not transitive: § R_5={(a,b)│a=b+1} (note that (3,2),(4,3)∈R_5, but (3,3)∉R_5), § R_6={(a,b)│a+b≤3} (note that (2,1),(1,2)∈R_6, but (2,2)∉R_6). Combining Relations • Given two relations R_1 and R_2 • We can combine them using basic set operations to form new relations • Example ○ Let A={1,2,3} and B={1,2,3,4} ○ The relations R_1 = {(1,1),(2,2),(3,3)} and R_2 = {(1,1),(1,2),(1,3),(1,4)} can be combined using basic set operations to form new relations: ○ R_1 ∪ R_2 ={(1,1),(1,2),(1,3),(1,4),(2,2),(3,3)} ○ R_1 ∩ R_2 ={(1,1)} ○ R_1 − R_2 ={(2,2),(3,3)} ○ R_2 − R_1 ={(1,2),(1,3),(1,4)} Inverse • Definition ○ Let R be a relation from A to B ○ The inverse of R is the relation § R^(−1)={(a,b)│(b,a)∈R} • Proposition ○ R is symmetric if and only if R=R^(−1) Composition • Definition ○ Suppose § R_1 is a relation from a set A to a set B. § R_2 is a relation from B to a set C ○ Then the composition of R_2 with R_1 is a relation from A to C where § if (x,y) is a member of R_1 § and (y,z) is a member of R_2 § then (x,z) is a member of R_2∘R_1 • Example ○ R_2∘R_1={(b,x),(b,z)} Powers of a Relation • Definition ○ Let R be a binary relation on A ○ Then the powers R_n of the relation R can be defined inductively by: ○ Basis Step: R_1=R ○ Inductive Step: R_(n+1)=R_n∘R • The powers of a transitive relation are subsets of the relation • This is established by the following theorem: • Theorem 1 ○ The relation R on a set A is transitive iff R_n⊆R for n = 1,2,3… ○ (see the text for a proof via mathematical induction)
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